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Calculus1
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so find for me the derivertive of thise one 3x^2+siny^2+y=e^4x
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derivative with respect to ??? (x or y)
with respect to x @PATTOOO
6x=4*e^4x other y terms will be 0
thise is an implicit diffriatiation hence findin dy/dx can be found differently and y can not be zero
ohh sry
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\[\sin(y^{2}) = e^{4x}-3x^{2} \] \[2 y cos(y^{2}) \frac{dy}{dt}=4e^{4x}\frac{dx}{dt}-6x\frac{dx}{dt}\] \[\frac {dy} {dt}(2ycos(y^2)) = \frac{dx}{dt}(4e^{4x}-6x)\] \[y'=\frac{(2e^{4x}-3x)sec(y^2)}{y}\]
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