Question

Find 3 consecutive odd numbers where the product of the smaller two numbers is 34 less than the square of the largest number.

Answer 1

you can say the consecutive number is x

Answer 2

i'll try

Answer 3

so three odd number are x , x+2 and x+4

Answer 4

now you can say the product of 2 smaller number is x(x+2)

Answer 5

square of the largest number is (x+4)^2

and less than 34 is (x+4)^2-34

Answer 6

so it will be x(x+2) = (x+4)^2-34

Answer 7

can you solve now

Answer 8

i can try

Answer 9

x^2+2x = x^2 + 2(x)(4) + (4)^2 -34
x^2+2x = x^2 + 8x +16 -34
x^2-x^2 = 8x - 2x +16 -34
18 = 6x
18 / 6 = x
x= 3