Question

Write the equation of the line in slope-intercept form that passes through the point (3, -2) and has a slope of 2.

y = 2x - 8

y = 2x - 4

y = 2x + 7

y = 2x + 5

Answer 1

we will be using y = mx + b and solving for b
slope(m) = 2
(3,-2) x = 3 and y = -2
now we sub
y = mx + b
-2 = 2(3) + b
-2 = 6 + b
-2 - 6 = b
-8 = b
therefore, your equation is : y = 2x - 8