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The question is Write the equation of the line that is perpendicular to the line 3x + y = 7 and passes through the point (6, −1). please help
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This is algebra 1
please help
First, solve for Y. Y = -3X+7 Now you have the slope, -3. Perpendicular, you need the opposite reciprocal of the slope. \[Y =\frac{ 1 }{ 3 }X + 7\]
Now you have the slope, take off the +7 and Plug in the points
-1 = (1/3)*6 + b -1 = 2 + b. solve for b.
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Do you get it now?
yeah and b is the y intercept right
Yep.
thanks for the help
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