Question

Solve, using the substitution method.

j + k = 3
j – k = 7

(Points : 1)
The solution is (8, 1)
The solution is (5, –2)
There is no solution.
There are an infinite number of solutions.

Answer 1

j + k = 3
j – k = 7 --> j = k + 7

j + k = 3 --> (k + 7) + k = 3
k + 7 + k = 3
2k + 7 = 3
-7 -7
2k = -4
k = -2 <-- (which option has a -2 in it? :P )

Answer 2

the solution is (5,-2)

Answer 3

Thank you guys.