4. Solve, using the substitution method.

y – 2x = 8
16 + 4x = 2y

(Points : 1)
The solution is (24, 0).
The solution is (1, 10).
There is no solution.
There are an infinite number of solutions.

Question 5.5. Solve, using the substitution method.

y = 3x + 5
4x – y = 5

(Points : 1)
(10, 35)
(15, 10)
There are an infinite number of solutions.
There is no solution.

Question

4. Solve, using the substitution method.

y – 2x = 8
16 + 4x = 2y

(Points : 1)
       The solution is (24, 0).
       The solution is (1, 10).
       There is no solution.
       There are an infinite number of solutions.


Question 5.5. Solve, using the substitution method.

y = 3x + 5
4x – y = 5

(Points : 1)
       (10, 35)
       (15, 10)
       There are an infinite number of solutions.
       There is no solution.

shamil98 · Answer

y = 2x + 8
simplify the second one by dividing by 2..
so your new system is:
y = 2x + 8
8 + 2x = y
substitute for y and solve for x. then plug in the value of x into one of the equations to get y.