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OpenStudy (anonymous):

AC Method 16h^2+24h+9 16h^2+12h+12h+9 4h(4h+3)3(4h+3) (4h+3) (4h+3) Do i combine that or keep it like it is.

OpenStudy (anonymous):

what is the question asking you to do?

OpenStudy (anonymous):

is it asking you to factor?

OpenStudy (anonymous):

Factor the trinomials using the ac method

OpenStudy (anonymous):

you can rewrite (4h+3)(4h+3) as: (4h+3)^2

OpenStudy (anonymous):

you have the right answer

OpenStudy (anonymous):

the answer is either: \[(4h+3)(4h+3)\] or\[(4h+3)^2\]

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