Question

x^2+3=9x
Can someone show me how to solve this?

Answer 1

\[x ^{2}+3=9x\]

Answer 2

move the 9x to the other side.
x^2 - 9x + 3 = 0
and now you use the quadratic formula.
\[\huge x= \frac{ -b \pm \sqrt {b^2 -4ac} }{ 2a }\]

Answer 3

ax^2 + bx + c = 0
get your values of your equation from this form.

Answer 4

I don't really understand

Answer 5

Once you have it n the form ax^2 +bx + c = 0

then use the formula given above to get x.

So

x^2 - 9x + 3 = 0

has a=1, b=-9, c=3

x = [9 +- sqrt(81-12)/2 = (9 + 8.3)/2 = 8.65 and [9 -8.3]/2 = 0.35

both values of x should solve the equation

check x=.35, and the equation = 0 [within rounding errors]

x=8.65 also gives 0 w/in rounding errors.: