You invested $9000 between two accounts paying 6% and 8% annual interest, respectively. If the total interest earned for the year was $649, how much was invested at each rate?

$____ was invested at 6% and $____ was invested at 8%.

Question

You invested $9000 between two accounts paying 6% and 8% annual interest, respectively. If the total interest earned for the year was $649, how much was invested at each rate?

$____ was invested at 6% and $____ was invested at 8%.

tkhunny · Answer

Name the investments!

$S was invested at 6% and $E was invested at 8%

Now, translate the pr4oblem statement in terms of S and E.

"You invested $9000 between two accounts"

"the total interest earned for the year was $649"

Go!

Show ANY work.  Do it!

anonymous · Answer

(9000-x) (0.06) + x (0.08) = 649

540 - 0.06 x + 0.08 x = 649

0.02 x = 649 - 540 = 109

x = 5450    and (9000-5200) = 3550

checks

tkhunny · Answer

Of course, actually WRITING DOWN the definition of 'x' would have been an excellent first step.