Question

4tan^4x+tan^2x-3=sec^2x(4tan^2x-3) verify

Answer 1

let x= tan^2x and then solve

Answer 2

you cant use both sides of equation

Answer 3

4tan^4x+tan^2x-3=sec^2x(4tan^2x-3)
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Factor the left side.
4*tan^4x+tan^2x-3 =
(4 tan² x - 3 ) * (tan²x + 1)

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On the right side, sec^2x(4tan^2x-3),
substitute (1+ tan² x) for sec²x to get:

(1+ tan² x) * (4*tan² x-3) =

(4*tan² x-3) * (tan² x + 1)

Now, compare the left and right sides.