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OpenStudy (anonymous):
verify cscxsecx=2csc2x please help me!!!!!!!
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OpenStudy (arthur_ser):
cscxsecx=2csc2x (1/sinx)(1/cosx)=2(1/sin2x) sinxcosx=1/2(sin2x) 2sinxcosx=sin2x
OpenStudy (anonymous):
if you need help with Trig identities go to this site it tell all the steps to get answers http://symbolab.com/solver/trigonometric-identity-calculator
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