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Someone please help me with this easy rational equation!! I will be forever in your debt
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x/(x+1)<x/(x-1)
hmm how would you solve , say \(\bf \cfrac{x}{x+1}=\cfrac{x}{x-1}\quad ?\)
I'd have to multiply for the LCM. But I don't know hw to do that, or what's the LCM of (x+1) and x-1
well.... or just "cross-multiply"
well, you'd do the same in the \(\Large <\) case, you cross-multiply
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\[\frac{ x }{x+1}<\frac{ x }{ x-1 }\] \[x(x-1)<x(x+1)\] \[x ^{2}-x<x ^{2}+x\] \[-2x<0\] \[x>0\]
Thank you all so much!!!
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