Question

Suppose an astronaut drops a feather from 1.2 m above the surface of the Moon. If the acceleration due to gravity on the Moon is 1.62 m/s2 downward, how long does it take the feather to hit the Moon's surface? s

Answer 1

use the kinematic equation:
s = s + vt + (1/2)at^2

plug in what we know:
0 = 1.2 + 0 + (1/2)(-1.62)t^2
solve for t

Answer 2

ohh i gotacha thank you!!

Answer 3

hes wrong

Answer 4

@zachy1234
what would you suggest as a solution?