PLEASE HELP?!?! :))
Find the x and y values at the minimum of 2x^2+xy+2y^2+3y+2
And find the x and y values at the maximum of
-3x^2+2xy-4y^2+2y+7

Question

PLEASE HELP?!?! :))
Find the x and y values at the minimum of 2x^2+xy+2y^2+3y+2
And find the x and y values at the maximum of 
-3x^2+2xy-4y^2+2y+7

phi · Answer

sounds like calculus.  Did you find the derivative of
 2x^2+xy+2y^2+3y+2

phi · Answer

It looks like you have
f(x,y) = 2x^2+xy+2y^2+3y+2
and you need to find the partial derivatives  fx  and fy
set both = 0 and solve for x and y

anonymous · Answer

is it ok if you can walk me through this process? pleasse? :)