Question

The width of a rectangle is twice its length. If the perimeter is at most 72 cm, what is the greatest possible value for its length?

The width of a rectangle is twice its length. If the perimeter is at most 72 cm, what is the greatest possible value for its length?

A. Write the formula for perimeter.

B. Write the algebraic inequality for this problem.

C. Solve the problem from Part B.

D. Answer the question in the problem.


Thank you!

Answer 1

a) 2length + 2Width = perimenter

Answer 2

b) 2(x) + 2(y) = Perimeter
2x = y