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Find the slope of the tangent line to the graph y = x^-3 at the point (0.5, 8).
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what does the term tangent mean in this context?
The derivative.
Find dy/dx and sub in 0.5
the derivative of the function is -3x^-2
How do I find it at that point?
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I got -12
Do I need to plug in 8 also?
-12 is the slope.........
if you plugged in both you wouldn't have any variables...
okay and so -12 would be my answer
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