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Please help! A pair of dice is tossed and the sum of the two dice is calculated. find the probability the sum is less than 11.
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I think its 11/12
if you think about it, out of the 36 possible pairs of numbers that the dice can show, only (6,6) (2 sixes) gets you a sum more than 11. the rest all give you less than 11 (except (6,5) and (5,6) which are 11 exactly)
so instead of finding Pr(<11), find 1-Pr(>11) (less work) 1- Pr (>11) = 1- Pr(6,6)-Pr(6,5)-Pr(5,6)
It would be 11/12
= 1 - (1/36) - (1/36) - (1/36) = 11/12 so yes you got it
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