Question

1/(xy)^+1 evaluate by using a negative exponent?

Answer 1

\[\huge \frac{ 1 }{ (xy)^1 } \] this?

Answer 2

or is it xy + 1

Answer 3

first one?

Answer 4

\[\huge \frac{ 1 }{ xy }\]
it's just that, since it's raised to the power of 1.

Answer 5

\[\huge 1 * (xy)^{-1}\]
is also the same thing

Answer 6

\(\bf a^{-n} = \cfrac{1}{a^n}\quad thus\quad \cfrac{1}{(xy)^1}\implies (xy)^{-1}\)

Answer 7

if that is what you are looking for.