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(a + b) ^0
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???
i just need to evaluate it?
\(\bf (a + b) ^0\qquad (cheese)^o\qquad (pizza)^0\qquad (watermelon)^o\qquad (tacos)^o\\ \quad \\ \textit{anything raised at 0, is }1\)
hmmm wait .. a sec...
nope... is correct... will also yield the same as anything else
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I think it is 1 for all (a+b) NOT equal to 0.
right, the only exception is 0 itself
Normally we say anything raised to zero is one. We also say zero raised to anything is zero. Then what is zero raised to zero? Is it one or zero. Answer: It is undefined.
The answer is a != b
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