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If A and B are second quadrant angles such that cos A = -2/5 and sin B = 3/7, find the exact value of sin (A-B). Express your answer as one fraction; you do not need to rationalize.
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\[\sin(A-B)=sinAcosB-cosAsinB\]
you still have to find \(\sin(B)\) and \(\cos(A)\) to finish this do you know how to do that?
Yes, but plugging in the values into the equation would not give a final fraction, right? My teacher wants me to have in answer in fraction form.
Okay never mind, I don't know what I'm doing now.
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