Question

Help?

Modify the declaration
int list[2][3];
so that
list[0][1]
is initialized to
-2
, and all other elements are initialized
to
0.

Answer 1

@jim_thompson5910

Answer 2

Any ideas @helpme1.2

Answer 3

int list[2][3]={{0,-2,0},{0,0,0}}; i think

Answer 4

int list [2][3]={{0,-2, 0},{0,0,0}};
for (int i=0; i<2;i++){
for (int j=0; j<3; j++){ cout <<list[i][j]; }cout<<endl;
}

Answer 5

Well if thats true how would that work for this?
int list[2][5][7]; Write an array loop that will display the value of every element of the array.

Answer 6

list[2][5][7] is three denominational array
list[2][3] is 2d

Answer 7

Okay yeah I knew that much.
How would you set it up though?

Answer 8

sorry it should be:
\(\color{blue}{\mbox{int }} \mbox{list}\color{red}{\mbox{[ ][ ]}}\mbox=\color{red}{\{\{}0,-2,0\color{red}\},\color{red}\{0,0,0\color{red}\}\color{red}\};\)

(I tested it)

Answer 9

And the question tells us to modify the declaration, so I think that it should be done in only 1 line.

Answer 10

write 3 loops

Answer 11

int list [2][3][5]={?}; for (int i=0; i<2;i++){ for (int j=0; j<3; j++){ for (int j=0; j<5; j++){ cout <<list[i][j]; }cout<<endl; }

Answer 12

Like that?

Answer 13

I tested my declaration. It worked. And the question asks for declaration. Not a bunch of for loops.

Answer 14

for (int i=0; i<2;i++){ for (int j=0; j<3; j++){ for (int m=0; m<5; m++){ cout <<list[i][j][m]; }cout<<endl; }

Answer 15

you can use this, but like @kc_kennylau said, you probably don't need to use loops

Answer 16

Thanks guys! :D

Answer 17

no problem :)

Answer 18

you're welcome