The coordinates of n ABC are A(0, 5), B(8, 20), and C(0, 26). Find the length of each side and the perimeter of n ABC. Then ﬁ nd the perimeter of the triangle formed by connecting the three midsegments of n ABC.

Question

The coordinates of n ABC are A(0, 5), B(8, 20), and C(0, 26). Find the length  of each side and the perimeter of n ABC. Then ﬁ nd the perimeter of the triangle  formed by connecting the three midsegments of n ABC.

anonymous · Answer

Get each side from  L = sqrt( (x1-x2)^2 + (y1-y2))^2

So AB is L = sqrt((0-8)^2 + (5-20)^2)

L = sqrt(64+ 225) =17

Do same for BC and CA

Perimeter is the sum of the three sides.

wolf1728 · Answer

cayytherine
I don't know if you've already determined the answer but I have made a graphic of the triangle and determined the lengths of all 3 sides.
If nothing else, see the attached graphic just to check your answers.

wolf1728 · Answer

I can't believe I made a mistake.  Line AC = 21 and NOT 25.
So the perimeter = 48

(The mistake I made was simply subtraction - no trig no geometry)
LOL