Question

identify one of the factors of 32r^2+24ry-4xr-3xy

Answer 1

8r(4^2+3y)
i can't do more.... CONFUSING!!!

Answer 2

I don't know if what i did till now is right or not...

Answer 3

alright thanks though and are ther more people in the morning

Answer 4

since its pretty late

Answer 5

to help out

Answer 6

32r^2+24ry-4xr-3xy

Let's factorize the first two terms:
32r^2+24ry
^ What are the common factors of these two terms?

Answer 7

i wanna say 2r,r

Answer 8

i'd say '8' and 'r'
Take the Highest Multiple...
I'll leave the Rest to Callisto

Answer 9

Let's say, we pick 2r out:
32r^2+24ry
= 2r(16r+12y)
It seems we can further factorize (16r+12y). What is the common factor in these two terms?

Answer 10

4,2,1

Answer 11

right ?

Answer 12

Take the largest one :) If you take 2, then we can further factorize it again. At last, we'll get 4 :D
So, we pick 4 out.
32r^2+24ry
= 2r(16r+12y)
= 2r [ 4 (4r + 3y) ]
= 8r (4r+3y)
So far so good?

Answer 13

yea is that the answer though ?

Answer 14

No.
Now, factorize the last two terms:
What are the common factors of -4xr-3xy?

Answer 15

i got -1, and -x

Answer 16

Which one should you pick?

Answer 17

umm -1 ?

Answer 18

Why?

Answer 19

wait but its negative.

Answer 20

thex could be before riight.

Answer 21

You can take out both -1 and x

Answer 22

Now, it's your turn to factorize -4xr-3xy. Can you give it a try?

Answer 23

i got -x(4r+3y)

Answer 24

Right.
So, for 32r^2+24ry-4xr-3xy, we get:
32r^2+24ry-4xr-3xy
= 8r (4r+3y) -x(4r+3y)
Is it clear to you?

Answer 25

yess so thats the final answer or no lol.

Answer 26

No, one more step.

Answer 27

okie dokie

Answer 28

factor the last one ?

Answer 29

Factorize this: 8r (4r+3y) -x(4r+3y)

Answer 30

i got (4r+3y) and (8r-x)

Answer 31

When you factorize by grouping, you make it into factored form..So, it is
(8r-x)(4r+3y)

Answer 32

and my choices are 1. (x-8r) 2. (8x-r) 3. (4r+3y) 4. none and 5. (3r+4y)

Answer 33

so i choose 3 right ?

Answer 34

Yes.

Answer 35

Wow your an expert thank you so much.

Answer 36

You're welcome :)