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(1+Tan(x))/(1+Cot(x))=(1-Tan(x))/(Cot(x)-1) Trig identity Question
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\[\frac{ 1+\tan(x) }{ 1+Cot(x) }=\frac{ 1-Tan(x) }{ Cot(x)-1 }\]
from the left hand side, do as you did in previous post, you get tan x , then do something like this |dw:1386532253888:dw|
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