Question

6

Answer 1

x^2 - 6x + 10 = 0
Roots are given by x = -b + sqrt(b^2 - 4ac)/2a , - b + sqrt(b^2 - 4ac)/2a

Answer 2

U will get the answer f u substitute the values in that formula

Answer 3

@ganibl i think its a

Answer 4

-3 + i will be one root

Answer 5

so b? or was i right with a? @ganibl

Answer 6

Its b but lets just make sure by solving :)

Answer 7

x^2 - 6x + 10 = 0
Roots are given by x = -b + sqrt(b^2 - 4ac)/2a , - b + sqrt(b^2 - 4ac)/2a

x = -(-6) + sqrt((-6)^2-4(1)(1))/2
x = 6 + sqrt(36-40)/2
x = 6 + sqrt(-4)/2
x = 6 + 2i/2
x = 3 + i