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Trigonometry 21 Online
OpenStudy (anonymous):

Prove (sinx + sin2x) / (1+cosx + cos2x) = tanx

OpenStudy (mathstudent55):

By sin2x and tan2x you mean \(\sin^2x\) and \(\tan^2 x\) or \(\sin (2x)\) and \(\tan (2x)\)?

OpenStudy (anonymous):

sin(2x) and cos(2x)

OpenStudy (jdoe0001):

\(\bf \cfrac{sin(x)+sin(2x)}{1+cos(x)+cos(2x)}\\ \quad \\ \textit{recall that }sin(2x)=2sin(x)cos(x)\qquad cos(2x)=2cos^2(x)-1\\ \quad \\ \cfrac{sin(x)+sin(2x)}{1+cos(x)+cos(2x)}\implies \cfrac{sin(x)+2sin(x)cos(x)}{\cancel{1}+cos(x)+2cos^2(x)\cancel{-1}}\) now, take common factors atop and bottom, see what you get

OpenStudy (anonymous):

Ohhh got it thanks :)

OpenStudy (jdoe0001):

yw

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