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OpenStudy (anonymous):
In square ABCD, AE=3x+5 and BD=10x+2. What is the length of segment AC? answer choices are.... A.2 B.11 C.22 D.32
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OpenStudy (anonymous):
|dw:1386546523809:dw|
OpenStudy (anonymous):
D
OpenStudy (anonymous):
Thank you !
OpenStudy (ranga):
In a square, the diagonals are the same length. Therefore, AC = BD BD = 10x + 2 (given). So AC = 10x + 2 Also AE is half of AC or two times AE = AC AE = 3x + 5 AC = 2 * AE 10x + 2 = 2(3x + 5) 10x+2 = 6x+10 10x - 6x = 10 - 2 4x = 8 x = 2 So AC = 10x+2 = 10(2) + 2 = 20 + 2 = 22. Answer: C.
OpenStudy (anonymous):
Yea hes right
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