Question

The specific heat of aluminum is 0.22 cal/g-ºC. What is the value of the specific heat in (a) kcal/kg-ºC, (b) J/kg-ºC? (Show your calculations)

Answer 1

You can do it as a conversion problem using
\[1 \ \text{cal}=1000 \ \text{kcal}\]
\[4.2 \ J=1 \ \text{cal} \ \quad ;\text{or} \quad 4200 J=1 \text{kcal}\]

Answer 2

Well that's wrong, sorry

Answer 3

\[1000 \text{cal} = 1 \text{kcal}\]

Answer 4

ie
\[\left( \frac{.22 \ \text{cal}}{g \ ºC}\right) \left(
\frac{1 \ \text{kcal}}{1000 \ \text{cal}} \right) \left( \frac{1000 g}{1 kg} \right) =\frac{.22 \ \text{kcal}}{kg ºC} \]

Answer 5

i know how ... laughing out loud I just can't copy and paste my math type into latex

Answer 6

:P yah, equation editors aren't really compatible with each other...

Answer 7

screen shots! ^_^

Answer 8

it used to allow me to do it but for some reason it is giving me errors this time

Answer 9

it might be the degree sign for some reason? - that's what the masculine ordinal is

Answer 10

\[\begin{gathered}
a) \hfill \\
\frac{{0.22cal}}{{g - C}} \times \frac{{1.00kcal}}{{1.00 \times {{10}^3}cal}} \times \frac{{1.00 \times {{10}^3}g}}{{1.00kg}} \cong \frac{{0.22kcal}}{{kg - C}} \hfill \\
\frac{\begin{gathered}
b) \hfill \\
0.22cal \hfill \\
\end{gathered} }{{g - C}} \times \frac{{4.186J}}{{1.00cal}} \times \frac{{1.00 \times {{10}^3}g}}{{1.00kg}} \cong \frac{{920J}}{{kg - C}} \hfill \\
\end{gathered} \]

OMGGGGGGG

Answer 11

\[\begin{array}{l}
a)\\
\frac{{0.22cal}}{{g - C}} \times \frac{{1.00kcal}}{{1.00 \times {{10}^3}cal}} \times \frac{{1.00 \times {{10}^3}g}}{{1.00kg}} \cong \frac{{0.22kcal}}{{kg - C}}\\
\frac{\begin{array}{l}
b)\\
0.22cal
\end{array}}{{g - C}} \times \frac{{4.186J}}{{1.00cal}} \times \frac{{1.00 \times {{10}^3}g}}{{1.00kg}} \cong \frac{{920J}}{{kg - C}}
\end{array}\]

Answer 12

weird.... \hfill must be something that the latex package on the site doesn't use - it has things like \hspace and \hline. Dunno.

Anyways, looks good methinks - on the first one though, I think you can use a definite equal sign, because the conversions are exact.

Answer 13

it was a different format or version of tex I used

Answer 14

so nothing is working anymore, basically :P At least the site isn't crashing (for the moment)....

Answer 15

haha

Answer 16

In any case, good luck with formatting fun!

Answer 17

^_^