Question

Help with logarithms please!

4^11x = 4^15 * (4^5x)^2

solve for x

Answer 1

\[\huge 4^{11\color{red}x}= 4^{15}\cdot (4^{5\color{red}x})^2\]
Am I right? ^_^

Answer 2

yes

Answer 3

Doesn't look too bad :)
First, simplify the right-side into just one base....

Answer 4

so log11x=log15 * log10x?

Answer 5

Easy there... all I asked was for you to simplify the right-side into just one base (4)
because you can...
It makes it easier, trust me ^^

Answer 6

ok so