Question

MEDALS FOR BEST ANSWERS

Answer 1

2. Simplifly 3-2x/7 + 4x+5/7
a. 2x+8/14
b. 2x+8/7 <---
c. x+1/7
d. 2x+2/7

3. Simplify 6ab^6/4a^7b^10 * a^3b^4/2a^7b^6
a. 7x/8 - 2x/8
b. -5x/8
c. 3a^2b^3/4a^7b^8
d. a^2b^5/2a^7b^8

4. Simplify 15x+3/27x-18 * 3x-2/5x+1
a. 7-2x/2x-18
b. 3
c. 7-2x/x-9
d. 5-15x/x+5 + 8x+8/x+5

5. 5x/x+9
a. -5x/x+9
b. 1
c. 8x/x-2 - 21x/x-2
d. 13x/x-2

Answer 2

What's the question?

Answer 3

Oh my.

Answer 4

its so difficult

Answer 5

Yeah!

Answer 6

its 10 problems to do :(

Answer 7

OOOOOOOOOH I see.

Answer 8

Do you think you could help me?..

Answer 9

No! Sorry!

Answer 10

well for number one excluded values are when you plug in that value and the answer you get is 0. So for 4x/6 the excluded value should be 3/2 but that is not an answer choice

Answer 11

its okay! and i know. I dont understand why my teacher would give me these multiple choices. @jennaknight_03

Answer 12

thats hard wut ur doing

Answer 13

Do you think the other ones are easier to help with or no

Answer 14

no. I ish I can help.

let me see if my friends can help

Answer 15

@UsArmy3947 @Jonathan1997

Answer 16

@Luigi0210

Answer 17

okay!

Answer 18

please help @selenaannerios with this question.

Answer 19

-_- why did u tag me?

Answer 20

please help @selenaannerios

Answer 21

@Jonathan1997

Answer 22

@selenaannerios I think @Jonathan1997 can help u

Answer 23

I can try....

Answer 24

um @selenaannerios ?

Answer 25

im sorry i was busy.

Answer 26

@Jonathan1997 can try 2 help

Answer 27

okay!

Answer 28

@Jonathan1997 did u find any out?

Answer 29

lol

Answer 30

@Jonathan1997 ?
r u there?

Answer 31

?

Answer 32

ok let me get another amigo.

Answer 33

Okay

Answer 34

@Luigi0210 please help

Answer 35

https://www.google.com/url?sa=t&rct=j&q=&esrc=s&source=web&cd=5&cad=rja&ved=0CEQQFjAE&url=http%3A%2F%2Fwww2.seminolestate.edu%2Frrapalje%2FIntermediateAlgebra%2FInt%2520One%2520Step%2520Ch%25202%2F2201_Factoring.htm&ei=LDemUp6SJImuyQHst4D4CA&usg=AFQjCNFdjg5KZJi2XImcBD3rVjOvodLa9A&sig2=_uVBEcHPPuUoI0Nad8TH0g&bvm=bv.57799294,d.aWc