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Evaluate \[ \lim_{x \to (\pi/2)^-}\: cos(x)sec(5x) \]
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\[\lim_{x\to\pi/2^-}\frac{\cos x}{\cos5x}=\frac{0}{0}\] Apply L'Hopital's rule, if you know it.
Does the - in the limit affect the answer? I get 1/5
http://www.wolframalpha.com/input/?i=limit+of+cos+x+sec+5x+as+x+goes+to+%28pi%2F2%29%5E-
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