You have an open question:

a roller coaster car is loaded with passengers and has a mass of 500 kg along with a speed of 18 meters/seconds at the dip. The radius of curvature of the track at the bottom point of the dip is 12 meters ( gravity = 9.8 meters/second^2) what force is extered on the roller coaster car by the track at the bottom of the dip.?

Question

You have an open question:

a roller coaster car is loaded with passengers and has a mass of 500 kg along with a speed of 18 meters/seconds at the dip. The radius of curvature of the track at the bottom point of the dip is 12 meters ( gravity = 9.8 meters/second^2) what force is extered on the roller coaster car by the track at the bottom of the dip.?

anonymous · Answer

You have supporting the force of gravity, m g, = 500kg (9.8 N/kg) 
plus the centripetal force m v^2 / R = 500kg (18m/s)^2 /12m