Question

Finding a line perpendicular to two parallel lines (parametric equations)?

If line L1 has parametric equations
x = 1+t
y = 3-2t
z = -2+2t

L2 has equations:
x= 4+s
y = 2-2s
z = -1+2s

Find parametric equations for the line perpendicular to L1 and L2.

What I did was find the directional vectors of the lines and crossed them (d1 x d2) to find the directional vector perpendicular to them which gave me [0,0,0].

so, I couldn't find any valid equation.