Question

what is the simplest form of the expression
sqrt2-sqrt6 over sqrt2+sqrt6

Answer 1

\[\sqrt{2}-\sqrt{6} \div \sqrt{2} + \sqrt{6}\]

Answer 2

i think its 1

Answer 3

you are kidding me @chinenyeogueri

Answer 4

multiply the conjugate of the denominator to the denominator and the numerator :)

Answer 5

@kc_kennylau damn i said i think get the flutter out

Answer 6

?

Answer 7

\[\frac{\sqrt2-\sqrt6}{\sqrt2+\sqrt6}=\frac{(\sqrt2-\sqrt6)(\sqrt2-\sqrt6)}{(\sqrt2+\sqrt6)(\sqrt2-\sqrt6)}=\frac{(\sqrt2-\sqrt6)^2}{2-6}\]