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\[\frac{9x+2}{x+2}>5\]\[\frac{9x+2}{x+2}\color{red} {\times(x+2)}>5\color{red} {\times(x+2)}\] can you do it now?
Just preform the multiplication, you will see that the denominator on the left hand side disappears.\[9x+2>5x+10\]\[9x+2\color{red} {-5x}>5x+10\color{red} {-5x}\]\[4x+2>10\]\[4x+2\color{red} {-2}>10\color{red} {-2}\]\[4x>8\]\[4x\color{red} {\div 4}>8\color{red} {\div 4}\]\[x>2\]
I got the answer of 6/4 .. Is that correct?
Ah Yah Correct .. x>2
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