Question

The length of a rectangle is 6 yards longer than its width. If the perimeter of the rectangle is 32 yd, find its area in square yards.

Answer 1

Area of a rectangle is L x W L - length W-width
Perimeter is 2L + 2W

Now they told us length is 6 yds longer than the width
so L = W + 6

Now since the perimeter is 32
We know
2L + 2W = 32
Substituting L = W + 6

2(W+ 6) + 2W = 32
Distributing
2 W + 12 + 2W = 32
Combining like terms
4W + 12 = 32

Subtract 12 from both sides
4W = 20

Dividing both sides be 4
W = 5

Now we have W
then L = W + 6 = 5 + 6 = 11

So L = 11 W = 5

so Area = L x W = 11 x 5 = 55 yd^2