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OpenStudy (anonymous):
can anyone help me solve the following :
1. Find the perimeter of your figure on the graph paper.
2. Find the area of your figure on the graph paper.
3. Use the key of 1 square = 2 feet for your top view picture. What would be the actual perimeter and area of your building?
Actual perimeter: Actual area:
OpenStudy (anonymous):
using this graph
OpenStudy (anonymous):
@CGGURUMANJUNATH @robtobey @travisbrown372
OpenStudy (cggurumanjunath):
count the number of boxes in the shaded region which gives your area ! @luka1998
OpenStudy (anonymous):
@CGGURUMANJUNATH what about the perimeter ?
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OpenStudy (anonymous):
@esshotwired
OpenStudy (anonymous):
@221emily help plz
OpenStudy (anonymous):
@charlotte123 help plz
OpenStudy (anonymous):
@SolomonZelman help plz
OpenStudy (cggurumanjunath):
add those numbers for the perimeter ! pic below .
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OpenStudy (cggurumanjunath):
@luka1998
OpenStudy (anonymous):
@CGGURUMANJUNATH the area=110 p=50 right ??
OpenStudy (anonymous):
@esshotwired
OpenStudy (esshotwired):
the area is 108 and the perimeter is 46
OpenStudy (anonymous):
@esshotwired how?/?
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OpenStudy (esshotwired):
all of the boxes in the shapes equal 108 and that is the area. then count how many boxes are along the edge of the shapes for the perimeter.
OpenStudy (anonymous):
ah thx
OpenStudy (esshotwired):
for the 3rd part the ratio for the area and perimeter would be 1:2 so pretty much just multiply the area and perimeter by 2 to get the actual area and actual perimeter
OpenStudy (anonymous):
p=46*2=92 a=108*2=216
OpenStudy (esshotwired):
yes
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OpenStudy (anonymous):
thx
can u help in another question that i will post ?