Question

Algebra 2 Review Please Help

Answer 1

I was either thinking A or D :/

Answer 2

@Euler271

Answer 3

We shall use this

Answer 4

Wark

Answer 5

i answered most of them I still have 20 to answer from where I am at

Answer 6

first one is A.

make sure you do:

\[\sqrt{-20} = \sqrt{-1}\sqrt{4}\sqrt{5} \]

Answer 7

Could you explain it after this though. Because the time limit is making me scared.

Answer 8

O yay

Answer 9

the second one is A, the one you chose

Answer 10

So the second is A?

Answer 11

ya -2 and 1/4

Answer 12

by limit do you mean the max/min?

Answer 13

is this class before or after calculus?

Answer 14

lol Before

Answer 15

And yes this is minimum and max

Answer 16

in that case, you have to complete the square to put it in its parabola form:

a(x - h)^2 + k

the value of a and the vertex (h, k) will give you all the info you need to know about it.

do you want to try or should i do it?

Answer 17

Lol please can you I am just trying to finish the rest but like the last 10 are all linear systems....

Answer 18

ill work it out skipping steps so you can come back to it some day:\[-[x^2 -3x + 2] = -[(x -\frac{ 3 }{ 2 })^2 - \frac{ 9 }{ 4 } + 2] = -[(x - \frac{ 3}{ 2 })^2 - \frac{ 1 }{ 4 }] = -1(x - \frac{ 3 }{ 2 })^2 + \frac{ 1 }{ 4 }\]
a < 0 so it opens downwards
(h, k), the vertex, is the point (3/2, 1/4)

it looks like this
max is 1/4
D, all real x
range y| less that or equal to 1/4

so sorry. i guess you worked it out already >.<.
its right

Answer 19

Haha yay its fine :3 I just glady ou helping :3

Answer 20

ill do it first and see if you have the right answer before explaining it lol.

i had solved it just then with latex

Answer 21

I was thinking B or C for this one

Answer 22

it's B