Question

Solve the quadratic equation y^2-7x-18=0

Answer 1

\[y^2=7x+18\]\[y=\pm\sqrt{7x+18}\]

Answer 2

\[\sqrt{7x+18}\]

Answer 3

y=+-sqrt(7x+18) and x>-7/18

Answer 4

you meant \[x^2-7x-18=0~~~~~~~~~~~~~~RIGHT?\]

Answer 5

\[(x+2)(x-9)=0\]from there you can do it on your own.