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OpenStudy (anonymous):
Factor x^2+3x+cx+3c
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hero (hero):
Factor x from x^2 + 3x to get x(x + 3) Factor c from cx + 3c to get c(x + 3) Observe that x^2 + 3x + cx + 3c factors to x(x + 3) + c(x + 3) Also observe that x + 3 is common to both factorizations. Therefore: x^2 + 3x + cx + 3c = x(x + 3) + c(x + 3) = (x + 3)(x + c)
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