find the solution of the initial value problem:

u''+u=F(t), u(0)=0 u'(0)=0

where F(t)= Ft, for 0

Question

find the solution of the initial value problem:

u''+u=F(t), u(0)=0 u'(0)=0

where F(t)= Ft, for 0<=t<=pi
                   F(2pi-t), for pi<t<=2pi
                   0 for      2pi<t
hint: treat each time interval sepereratly , and match the solutions in the different intervals by reqiuring u and u' to be continuous functions of t

the_fizicx99 · Answer

Not a clue lol sorry.

the_fizicx99 · Answer

Ask @Hero @agent0smith @shamil98

anonymous · Answer

my teacher gives the hardest problems for hw idk why

anonymous · Answer

thats the easy part

anonymous · Answer

ok

anonymous · Answer

so its Acost+Bsint right?

anonymous · Answer

just to clarify, what do we take the wronskin for?

loser66 · Answer

@ChristopherToni  Master, we need you  here

anonymous · Answer

yeah bro this is a step function

anonymous · Answer

so you got like (1-heaviside(t-pi)) for the first part right

anonymous · Answer

then we got some real shiz on that second part
heaviside(t-pi)*F(2pi-t)
right and the rest is a wrap