Question

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Answer 1

7. What is the solution to \[x=\sqrt{2x+3}\] ?

Answer 2

A.3
B.-1
C.3 and -1
D.-3 and 1

Answer 3

\[x=\sqrt{2x+3}\]square both sides
\[x^2=2x+3\]\[x^2-2x-3=0\]can you do it from there?

Answer 4

\[(x+1)(x-3)=0~~~~~~~~~~~~~~~~you~~~~tell~~~~me~!\]

Answer 5

1 & -3

Answer 6

Nope the other way,\[-1 ~~~~~~~~~~~~~and~~~~~~~~~~~~3\]

Answer 7

oh

Answer 8

-1 or 3 make it equal to zero, right?

Answer 9

yeah i see

Answer 10

\[(-1+1)(-1-3)=0~~~~~~~~~~~~~~OR~~~~~~~~~~~~~~(3+1)(3-3)=0\]

GOOD!!