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using vectors prove that the angle in a semicircle is a right angle.
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|dw:1386769910583:dw|
got it till here...
a = x,y b = c-x, -y
|a| = sqrt(x^2+y^2) |b| = sqrt((c-x)^2+y^2)
a.b = cx -x^2 - y^2 ----- ---------------------- = 0 if cx-x^2-y^2 = 0 |a||b| = sqrt(c^2+x^2 -2cx + y^2)
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Thank you! @ amistre64
show that the results of that have to fit a circle equation: (x-c/2)^2 + y^2 = (c/2)^2
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