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OpenStudy (praxer):
a= 2i^-3j^+k^ b=-i^+k^ c= 2j^-k^ find the are of the parallelogram having diagonals a+b and b+c...
ganeshie8 (ganeshie8):
hint : magnitude of cross product
OpenStudy (praxer):
but can it be that the side a be equal to the side b because if we draw and take the a to be the left side and b to the top and and bottom side and c to be the right than only it fall into the requirements but a is not equal to c.. So,, i am confused...
OpenStudy (praxer):
ganeshie8 (ganeshie8):
i need to go now, il tag an expert @ikram002p plese save us
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OpenStudy (ikram002p):
|dw:1386776251498:dw|
OpenStudy (ikram002p):
nw u oly need to find the cross product as ganesh said
OpenStudy (praxer):
which mean that the sides a and c are similar and are equal and opposite but can it be....
OpenStudy (ikram002p):
well ,r u sure from the vectors ??
OpenStudy (praxer):
yup I am sure.
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OpenStudy (ikram002p):
ok lets think of onther way
lets find
a+b
b+c
OpenStudy (ikram002p):
ok we have
a+b= i-3j+2k
b+c=-i+2j
OpenStudy (praxer):
ya..
OpenStudy (ikram002p):
|dw:1386777043167:dw|
OpenStudy (ikram002p):
but u can shift them to make them as diagonal |dw:1386777201791:dw|
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OpenStudy (praxer):
followed.
OpenStudy (ikram002p):
nw consider the properties of the parallelogram diagonals
they bisect each other