Question

PLEASE HELP WILL GIVE MEDAL !!!!

Answer 1

@RadEn

Answer 2

@PixieDust1

Answer 3

@SolomonZelman

Answer 4

\[a^2+b^2=c^2\]a and b are the two legs of the triangle
c is the hypotenuse.

you know the hypotenuse=28
and one of the legs is 14

So,
\[14^2+b^2=28^2\]\[196+b^2=784\]\[b^2=784-196\]\[b^2=588\]\[b=\sqrt{588}\]the exact value is \[b=\sqrt{49} \times \sqrt{4} \times \sqrt{3}=7 \times 2 \times \sqrt{3}=14\sqrt{3}\]the approximate value is,
\[24.25\]