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Simplify: (x - 8)^2
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(a - b)^2 = a^2 - 2ab + b^2
x^ - 16x + 64 is what u shd get if u expand it
if by simplify you mean multiply.
binomial theorem? \[(x-8)^2=\sum_{k=0}^{k=2}\left(\begin{matrix}2 \\ k\end{matrix}\right)x ^{2-k}-8^k\]
so: \[\left(\begin{matrix}2 \\ 0\end{matrix}\right)x^{2-0}(-8)^0+\left(\begin{matrix}2 \\ 1\end{matrix}\right)x^{2-1}(-8)^1+\left(\begin{matrix}2 \\ 2\end{matrix}\right)x^{2-2}(-8)^2\]
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\[x^2+(2)(x)(-8)+64\]
\[x^2-16x+64\]
i showed my simplifying steps
sorry to make it more complex than it really is
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