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A coin is tossed six times. What is the probability of obtaining at most five heads?
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1/64
For every toss, you have "1/2" probability of getting heads. So for 6 tosses, you have (1/2)^6 or 1/64
P(at most 5 heads) = 1 - P(6 heads) = 1 - (1/2)^6 = 63/64
the questions is asking for AT MOST 5 heads, NOT exactly 5 heads
Overlooked the problem... sorry for the confusion
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