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Mathematics 26 Online
OpenStudy (anonymous):

if f(x)=(4-2x)/2+3x+3x^2) , then what is the value of x for which f'(x)=0

OpenStudy (anonymous):

f'(x)= -2(2+3x+3x^2)-(4-2x)(3+6x)/(2+3x+3x^2)^2

OpenStudy (anonymous):

m sorry.. can u pls exaggerate?

OpenStudy (anonymous):

-4-6x-6x^2-12-24x+6x-12x^2/4+9x^3+9x^4

OpenStudy (anonymous):

i meant,can u explain?

OpenStudy (anonymous):

1 minet

OpenStudy (anonymous):

okay.. i understood.. u applied the u/v rule

OpenStudy (anonymous):

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