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OpenStudy (anonymous):
if f(x)=(4-2x)/2+3x+3x^2) , then what is the value of x for which f'(x)=0
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OpenStudy (anonymous):
f'(x)= -2(2+3x+3x^2)-(4-2x)(3+6x)/(2+3x+3x^2)^2
OpenStudy (anonymous):
m sorry.. can u pls exaggerate?
OpenStudy (anonymous):
-4-6x-6x^2-12-24x+6x-12x^2/4+9x^3+9x^4
OpenStudy (anonymous):
i meant,can u explain?
OpenStudy (anonymous):
1 minet
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OpenStudy (anonymous):
okay.. i understood.. u applied the u/v rule
OpenStudy (anonymous):
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