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solve for x 20x^2-7x=6
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\[20x^2-7x=6\]\[20x^2-7x\color{red} { -6 }=6\color{red} { -6 }\]\[20x^2-7x-6=0\]Now use the quadratic formula.
x=−2/5,3/4
\[\huge\color{green}{\frac{-b±\sqrt{b^2-4ac}}{2a}}\]
We are NOT giving out plain answers!!!!! @sirizarry78!!!
x=−2/5,3/4
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Guys stop giving out answers, the website is not for that!
Do you understand how to do it, @mili85?
(sorry, @milli85
nt really
im lost wen it comes to math
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\[\huge\color{red}{a}x^2+\huge\color{red}{b}x+\huge\color{red}{c}=0\]\[COMPARE~~~YOUR'S~~~TO~~THIS.\]\[\huge\color{red}{20}x^2\huge\color{red}{-7}x\huge\color{red}{-6}=0\] see the a b c? PLUG them into the quadratic formula.
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