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Mathematics 7 Online
OpenStudy (anonymous):

Verify the identity. 1-sin x/cos x=cos x/1+sin x

OpenStudy (anonymous):

I have to write it out also

OpenStudy (solomonzelman):

this can also be writens as 1-tanx=cosx+sinx

OpenStudy (solomonzelman):

\[1-tanx=cosx+sinx\]\[1-tanx-cosx=sinx\]\[1~~-(sinx+1)~/~cosx=sinx\]\[-sinx-1=sinx~cosx\]I don;t think this is an identity, it's an equation.

OpenStudy (anonymous):

well that's what the problem says! :) so you think that's how its worked out?

OpenStudy (solomonzelman):

Do you understand what I did?

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